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Popular >

xy^'-(x+1)y=0

Solution

x y^{^{'}} - (x + 1) y = 0

Solution

y = e^{x + c_{1}} x

Solution steps

x y^{'} (x) - (x + 1) y = 0

Solve separable ODE:

y = e^{x + c_{1}} x

y = e^{x + c_{1}} x

Popular Examples

xy^2cos(x)dx-3x^2ycos(x)dy=0,y(1)=1

x y^{2} cos (x) d x - 3 x^{2} y cos (x) d y = 0, y (1) = 1

(dP)/(dt)=2sqrt(Pt),P(1)=2

\frac{d P}{d t} = 2 Pt, P (1) = 2

\frac{d V}{d P} = - \frac{V}{P}

(dy)/(dx)=(3x+xy^2)/(2y-x^2y)

\frac{d y}{d x} = \frac{3 x + x y ^{2}}{2 y - x ^{2} y}

(1-x)(dy)/(dx)=y^2

(1 - x) \frac{d y}{d x} = y^{2}

Frequently Asked Questions (FAQ)

What is the solution for xy^'-(x+1)y=0 ?
The solution for xy^'-(x+1)y=0 is y=e^{x+c_{1}}x