What is the solution for y^'cos(x)+(3y-1)sec(x)=0,y(1/4 pi)= 4/3 ?

The solution for y^'cos(x)+(3y-1)sec(x)=0,y(1/4 pi)= 4/3 is y=e^{-3tan(x)+3}+1/3

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y^'cos(x)+(3y-1)sec(x)=0,y(1/4 pi)= 4/3

y^{^{'}} cos (x) + (3 y - 1) sec (x) = 0, y (\frac{1}{4} π) = \frac{4}{3}

y = e^{- 3 t a n (x) + 3} + \frac{1}{3}

Solution steps

y^{'} (x) cos (x) + (3 y - 1) sec (x) = 0

Solve separable ODE:

y = e^{- 3 t a n (x) + 3} + \frac{1}{3}

y = e^{- 3 t a n (x) + 3} + \frac{1}{3}

x^{^{'}} = \frac{1 + x}{1 + t}

y^{^{'}} + 2 x y^{2} = 0, y (0) = 1

y^{^{'}} = t^{2} y, y (0) = 1

(1 - ln (x)) d x + (1 - ln (y)) d y = 0, y (e) = e

f^{^{'}} (x) = (f (x))^{2}

What is the solution for y^'cos(x)+(3y-1)sec(x)=0,y(1/4 pi)= 4/3 ?
The solution for y^'cos(x)+(3y-1)sec(x)=0,y(1/4 pi)= 4/3 is y=e^{-3tan(x)+3}+1/3