en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^'=e^{-x}

Solution

x^{^{'}} = e^{- x}

Solution

x = ln (t + c_{1})

Solution steps

x^{'} (t) = e^{- x}

Solve separable ODE:

x = ln (t + c_{1})

x = ln (t + c_{1})

Popular Examples

(dy)/(dx)+y=6x^2y

\frac{d y}{d x} + y = 6 x^{2} y

y^2(dy)/(dx)=3x^2(y^3-2)

y^{2} \frac{d y}{d x} = 3 x^{2} (y^{3} - 2)

(dy)/(dx)=sin(3x)y^2

\frac{d y}{d x} = sin (3 x) y^{2}

(dy)/(dx)=(1+y)/(1+x)

\frac{d y}{d x} = \frac{1 + y}{1 + x}

(dy)/(dx)y=x^{sin(x)}

\frac{d y}{d x} y = x^{s i n (x)}

Frequently Asked Questions (FAQ)

What is the solution for x^'=e^{-x} ?
The solution for x^'=e^{-x} is x=ln(t+c_{1})