What is the solution for x+3y^2sqrt(x^2+1)(dy)/(dx)=0,y(0)=1 ?

The solution for x+3y^2sqrt(x^2+1)(dy)/(dx)=0,y(0)=1 is y=\sqrt[3]{-sqrt(x^2+1)+2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x+3y^2sqrt(x^2+1)(dy)/(dx)=0,y(0)=1

x + 3 y^{2} x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 1

y = 3 - x^{2} + 1 + 2

Solution steps

x + 3 y^{2} x^{2} + 1 \frac{d y}{d x} = 0

Solve separable ODE:

y = 3 - x^{2} + 1 + 2

y = 3 - x^{2} + 1 + 2

y^{^{'}} = \frac{1 - 2 x}{y}

\frac{d y}{d x} - 3 y = 12

(1 + y) y^{^{'}} = y

x^{^{'}} - 2 x = 4

x d x + (sin (y) + x^{2} sin (y)) d y = 0

What is the solution for x+3y^2sqrt(x^2+1)(dy)/(dx)=0,y(0)=1 ?
The solution for x+3y^2sqrt(x^2+1)(dy)/(dx)=0,y(0)=1 is y=\sqrt[3]{-sqrt(x^2+1)+2}