What is the solution for (dy)/(dx)=(y(x-y))/(x^2) ?

The solution for (dy)/(dx)=(y(x-y))/(x^2) is y= x/(ln(x)+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(y(x-y))/(x^2)

\frac{d y}{d x} = \frac{y ( x - y )}{x ^{2}}

y = \frac{x}{ln ( x ) + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{y ( x - y )}{x ^{2}}

Solve Bernoulli ODE:

y = \frac{x}{ln ( x ) + c _{1}}

y = \frac{x}{ln ( x ) + c _{1}}

\frac{d}{d x} (sin (x) \cdot cos (x) \cdot \frac{1}{x})

y = 6 x^{2}, y = 4 x^{2}, y = 6 - 5 x

\frac{d}{d x} (2 cos (x) + 2)

\frac{d}{d t} (e^{8 t})

\frac{d}{d x} (- \frac{1}{x ^{2}} - \frac{2}{x ^{3}})

What is the solution for (dy)/(dx)=(y(x-y))/(x^2) ?
The solution for (dy)/(dx)=(y(x-y))/(x^2) is y= x/(ln(x)+c_{1)}