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Popular >

y^'=-xy^2

Solution

y^{^{'}} = - x y^{2}

Solution

y = - \frac{2}{- x ^{2} + c _{1}}

Solution steps

y^{'} (x) = - x y^{2}

Solve separable ODE:

y = - \frac{2}{- x ^{2} + c _{1}}

y = - \frac{2}{- x ^{2} + c _{1}}

Popular Examples

(dy)/(dx)+5xy=8x,y(0)=4

\frac{d y}{d x} + 5 x y = 8 x, y (0) = 4

y^'=(x^2+1)/(2-y),y(-3)=4

y^{^{'}} = \frac{x ^{2} + 1}{2 - y}, y (- 3) = 4

(dP)/(dt)-aP(t)=b

\frac{d P}{d t} - a P (t) = b

(dy)/(dx)=-2/4 x^7y^5

\frac{d y}{d x} = - \frac{2}{4} x^{7} y^{5}

y^'+y/6 =2,y(-1)=0

y^{^{'}} + \frac{y}{6} = 2, y (- 1) = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=-xy^2 ?
The solution for y^'=-xy^2 is y=-2/(-x^2+c_{1)}