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Popular >

y^'=4x^3y^2

Solution

y^{^{'}} = 4 x^{3} y^{2}

Solution

y = - \frac{1}{x ^{4} + c _{1}}

Solution steps

y^{'} (x) = 4 x^{3} y^{2}

Solve separable ODE:

y = - \frac{1}{x ^{4} + c _{1}}

y = - \frac{1}{x ^{4} + c _{1}}

Popular Examples

y^'=(1-6x^2)/(2y+3)

y^{^{'}} = \frac{1 - 6 x ^{2}}{2 y + 3}

y^{^{'}} = - ln ∣ x ∣ y

xyy^'=1+y^2,y(1)=3

x y y^{^{'}} = 1 + y^{2}, y (1) = 3

(dy)/(dx)=((y-1))/(x^2sqrt(4+x^2))

\frac{d y}{d x} = \frac{( y - 1 )}{x ^{2} 4 + x ^{2}}

(dy)/(dx)-7e^{x-y}=0

\frac{d y}{d x} - 7 e^{x - y} = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=4x^3y^2 ?
The solution for y^'=4x^3y^2 is y=-1/(x^4+c_{1)}