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Popular >

y+4y^'+3y=0

Solution

y + 4 y^{^{'}} + 3 y = 0

Solution

y = e^{- t + c_{1}}

Solution steps

y + 4 y^{'} (t) + 3 y = 0

Solve separable ODE:

y = e^{- t + c_{1}}

y = e^{- t + c_{1}}

Popular Examples

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y^'sin(x)=yln(y),y(pi/2)=e

y^{^{'}} sin (x) = y ln (y), y (\frac{π}{2}) = e

Frequently Asked Questions (FAQ)

What is the solution for y+4y^'+3y=0 ?
The solution for y+4y^'+3y=0 is y=e^{-t+c_{1}}