en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=e^ysin(t)

Solution

y^{^{'}} = e^{y} sin (t)

Solution

y = - ln (cos (t) - c_{1})

Solution steps

y^{'} (t) = e^{y} sin (t)

Solve separable ODE:

y = - ln (cos (t) - c_{1})

y = - ln (cos (t) - c_{1})

Popular Examples

(1-y)(dy)/(dx)=x^2

(1 - y) \frac{d y}{d x} = x^{2}

(dy)/(dx)y=(sin(x))/(x^3)

\frac{d y}{d x} y = \frac{sin ( x )}{x ^{3}}

y^'=(ln(x))/(xy)

y^{^{'}} = \frac{ln ( x )}{x y}

(dy)/(dx)=-1/(sin(y)),y(-3)= pi/2

\frac{d y}{d x} = - \frac{1}{sin ( y )}, y (- 3) = \frac{π}{2}

(dy}{dx}(-ycot(x))=\frac{sin(2x))/2

\frac{d y}{d x} (- y cot (x)) = \frac{sin ( 2 x )}{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^ysin(t) ?
The solution for y^'=e^ysin(t) is y=-ln(cos(t)-c_{1})