en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y^')/x+y=1

Solution

\frac{y ^{^{'}}}{x} + y = 1

Solution

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 1

Solution steps

\frac{y ^{'} ( x )}{x} + y = 1

Solve separable ODE:

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 1

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 1

Popular Examples

sin(y)+1/2 xcos(y)(dy)/(dx)=3

sin (y) + \frac{1}{2} x cos (y) \frac{d y}{d x} = 3

y^{^{'}} = e^{x} e^{- y}

(dP)/(dt)=4sqrt(Pt),P(1)=5

\frac{d P}{d t} = 4 Pt, P (1) = 5

(x^2-1)(dy)/(dx)+2xy=x

(x^{2} - 1) \frac{d y}{d x} + 2 x y = x

(1-x^2)(dy)/(dx)+xy=x

(1 - x^{2}) \frac{d y}{d x} + x y = x

Frequently Asked Questions (FAQ)

What is the solution for (y^')/x+y=1 ?
The solution for (y^')/x+y=1 is y=-e^{-(x^2)/2-c_{1}}+1