What is the derivative of (1-x^2) ?

The derivative of (1-x^2) is -2(1-x)

What is the first derivative of (1-x^2) ?

The first derivative of (1-x^2) is -2(1-x)

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\frac{d}{d x} ((1 - x)^{2})

- 2 (1 - x)

Solution steps

\frac{d}{d x} ((1 - x)^{2})

Apply the chain rule:

2 (1 - x) \frac{d}{d x} (1 - x)

= 2 (1 - x) \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= 2 (1 - x) (- 1)

Simplify

= - 2 (1 - x)

f (x) = \frac{4 x + x ^{2}}{( 2 + x ) ^{2}}

\int_{0}^{3} 17 d x

6 y^{^{''}} + 6 y^{^{'}} - 12 y = 0

y = 2 x^{3} + 3 x^{2} - 12 x + 7

\int \frac{12 x}{1 + 4 x} d x

What is the derivative of (1-x^2) ?
The derivative of (1-x^2) is -2(1-x)
What is the first derivative of (1-x^2) ?
The first derivative of (1-x^2) is -2(1-x)