What is the solution for (x^2+1)(dy)/(dx)=x(y+1) ?

The solution for (x^2+1)(dy)/(dx)=x(y+1) is y=c_{1}sqrt(x^2+1)-1

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(x^2+1)(dy)/(dx)=x(y+1)

(x^{2} + 1) \frac{d y}{d x} = x (y + 1)

y = c_{1} x^{2} + 1 - 1

Solution steps

(x^{2} + 1) \frac{d y}{d x} = x (y + 1)

Solve separable ODE:

y = c_{1} x^{2} + 1 - 1

y = c_{1} x^{2} + 1 - 1

y^{^{'}} = \frac{( ( x - 2 ) ^{2} )}{y}, y (0) = 1

\frac{d y}{d x} = - \frac{3}{7} x^{6} y^{4}

\frac{d y}{d x} = \frac{y ln ( x )}{x}, y (1) = 0

(1 - x) y^{^{'}} - y = 0

d v = sin (x) d x

What is the solution for (x^2+1)(dy)/(dx)=x(y+1) ?
The solution for (x^2+1)(dy)/(dx)=x(y+1) is y=c_{1}sqrt(x^2+1)-1