What is the solution for (dy)/(dx)=y^2sin(x),y(0)=3 ?

The solution for (dy)/(dx)=y^2sin(x),y(0)=3 is y=-3/(-3cos(x)+2)

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(dy)/(dx)=y^2sin(x),y(0)=3

\frac{d y}{d x} = y^{2} sin (x), y (0) = 3

y = - \frac{3}{- 3 cos ( x ) + 2}

Solution steps

\frac{d y}{d x} = y^{2} sin (x)

Solve separable ODE:

y = - \frac{3}{- 3 cos ( x ) + 2}

y = - \frac{3}{- 3 cos ( x ) + 2}

\frac{d y}{d x} + x y = x y^{- \frac{1}{2}}

\frac{d x}{d t} = 37.5 - 3.5 x

(x + 1) y d x + y^{2} e^{x} d y = 0

\frac{d y}{d x} = \frac{4 x + x y ^{2}}{2 y + x ^{2} y}

(2 x + 1) d x + (5 - 6 y) d y = 0

What is the solution for (dy)/(dx)=y^2sin(x),y(0)=3 ?
The solution for (dy)/(dx)=y^2sin(x),y(0)=3 is y=-3/(-3cos(x)+2)