What is the solution for (dy)/(dx)=(x^2)/(y^3) ?

The solution for (dy)/(dx)=(x^2)/(y^3) is y=\sqrt[4]{(4x^3)/3+c_{1}},y=-\sqrt[4]{(4x^3)/3+c_{1}}

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(dy)/(dx)=(x^2)/(y^3)

\frac{d y}{d x} = \frac{x ^{2}}{y ^{3}}

y = 4 \frac{4 x ^{3}}{3} + c_{1}, y = - 4 \frac{4 x ^{3}}{3} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{x ^{2}}{y ^{3}}

Solve separable ODE:

y = 4 \frac{4 x ^{3}}{3} + c_{1}, y = - 4 \frac{4 x ^{3}}{3} + c_{1}

y = 4 \frac{4 x ^{3}}{3} + c_{1}, y = - 4 \frac{4 x ^{3}}{3} + c_{1}

y^{^{'}} + x^{3} y = 0

\frac{d x}{d y} = \frac{6 x 5 - 2 x + 1}{cos ( y ) + ey}

\frac{d y}{d t} = y

\frac{d h}{d t} = - \frac{3}{100} \cdot h - 18

y^{^{'}} - 4 x y^{2} = 0

What is the solution for (dy)/(dx)=(x^2)/(y^3) ?
The solution for (dy)/(dx)=(x^2)/(y^3) is y=\sqrt[4]{(4x^3)/3+c_{1}},y=-\sqrt[4]{(4x^3)/3+c_{1}}