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Popular >

y/x y^'+e^y=0

Solution

\frac{y}{x} y^{^{'}} + e^{y} = 0

Solution

y = - W (\frac{- x ^{2} + c _{1}}{2 e}) - 1

Solution steps

\frac{y}{x} y^{'} (x) + e^{y} = 0

Solve separable ODE:

y = - W (\frac{- x ^{2} + c _{1}}{2 e}) - 1

y = - W (\frac{- x ^{2} + c _{1}}{2 e}) - 1

Popular Examples

(t^2-22t+96)(dy)/(dt)=y

(t^{2} - 22 t + 96) \frac{d y}{d t} = y

(dy}{dx}=\frac{xsin(x))/y

\frac{d y}{d x} = \frac{x sin ( x )}{y}

(dy)/(dx)=2e^{x-y},y(1)=ln(2e+1)

\frac{d y}{d x} = 2 e^{x - y}, y (1) = ln (2 e + 1)

e^{3x}y-e^{5x}y^3y^'=0

e^{3 x} y - e^{5 x} y^{3} y^{^{'}} = 0

x \cdot y^{^{'}} + y = 0

Frequently Asked Questions (FAQ)

What is the solution for y/x y^'+e^y=0 ?
The solution for y/x y^'+e^y=0 is y=-\W((-x^2+c_{1})/(2e))-1