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Popular >

y^'=3x^2(y^2+1)

Solution

y^{^{'}} = 3 x^{2} (y^{2} + 1)

Solution

y = tan (x^{3} + c_{1})

Solution steps

y^{'} (x) = 3 x^{2} (y^{2} + 1)

Solve separable ODE:

y = tan (x^{3} + c_{1})

y = tan (x^{3} + c_{1})

Popular Examples

xy^2dx+(x^2y+3y)dy=0,y(1)=1

x y^{2} d x + (x^{2} y + 3 y) d y = 0, y (1) = 1

x^2y^2y^'=1+x^2

x^{2} y^{2} y^{^{'}} = 1 + x^{2}

x/y (dy)/(dx)=1

\frac{x}{y} \frac{d y}{d x} = 1

y^'=2xy^2,y(0)= 1/(4-x^2)

y^{^{'}} = 2 x y^{2}, y (0) = \frac{1}{4 - x ^{2}}

12sin(x)(dy)/(dx)=1ey-ye-y

12 sin (x) \frac{d y}{d x} = 1 ey - ye - y

Frequently Asked Questions (FAQ)

What is the solution for y^'=3x^2(y^2+1) ?
The solution for y^'=3x^2(y^2+1) is y=tan(x^3+c_{1})