What is the solution for (dy)/(dx)=(y+1)/(x-1) ?

The solution for (dy)/(dx)=(y+1)/(x-1) is y=e^{c_{1}}x-e^{c_{1}}-1

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(dy)/(dx)=(y+1)/(x-1)

\frac{d y}{d x} = \frac{y + 1}{x - 1}

y = e^{c_{1}} x - e^{c_{1}} - 1

Solution steps

\frac{d y}{d x} = \frac{y + 1}{x - 1}

Solve separable ODE:

y = e^{c_{1}} x - e^{c_{1}} - 1

y = e^{c_{1}} x - e^{c_{1}} - 1

\frac{d y}{d t} = y^{2} e^{- t}, y (0) = \frac{1}{2}

f^{^{'}} (x) = f (x)

y^{^{'}} = \frac{1 + x}{y}

sin (2 x) d x + cos (9 y) d y = 0, y (\frac{π}{2}) = \frac{π}{9}

\frac{d y}{d x} = (9 + y^{2}) (3 + x^{2})

What is the solution for (dy)/(dx)=(y+1)/(x-1) ?
The solution for (dy)/(dx)=(y+1)/(x-1) is y=e^{c_{1}}x-e^{c_{1}}-1