What is the solution for (x^2-9)y^'+xy=0,y(5)=1 ?

The solution for (x^2-9)y^'+xy=0,y(5)=1 is y= 4/(sqrt(x^2-9))

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(x^2-9)y^'+xy=0,y(5)=1

(x^{2} - 9) y^{^{'}} + x y = 0, y (5) = 1

y = \frac{4}{x ^{2} - 9}

Solution steps

(x^{2} - 9) y^{'} (x) + x y = 0

Solve separable ODE:

y = \frac{4}{x ^{2} - 9}

y = \frac{4}{x ^{2} - 9}

y^{^{'}} = y^{2} (x + 1), y (0) = 2

(1 + x^{2}) y^{^{'}} = sin (y)

\frac{3 d y}{2 d x} + \frac{4 x + 2 x y ^{2}}{2 y + x ^{2} y} = 0

y^{^{'}} - y = 3, y (0) = 0

y^{^{'}} = \frac{x}{3 - y}, y (2) = 0

What is the solution for (x^2-9)y^'+xy=0,y(5)=1 ?
The solution for (x^2-9)y^'+xy=0,y(5)=1 is y= 4/(sqrt(x^2-9))