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Popular >

y^'=14y+1

Solution

y^{^{'}} = 14 y + 1

Solution

y = \frac{e ^{14 t + c_{1}}}{14} - \frac{1}{14}

Solution steps

y^{'} (t) = 14 y + 1

Solve separable ODE:

y = \frac{e ^{14 t + c_{1}}}{14} - \frac{1}{14}

y = \frac{e ^{14 t + c_{1}}}{14} - \frac{1}{14}

Popular Examples

(csc(y))dx+(cos^2(x))dy=0

(csc (y)) d x + (cos^{2} (x)) d y = 0

sqrt(x-1)(dy)/(dx)= x/y ,y=1,x=2

x - 1 \frac{d y}{d x} = \frac{x}{y}, y = 1, x = 2

x y^{^{'}} + 2 y = y^{2}

(dy)/(dx)=-(xy)2

\frac{d y}{d x} = - (x y) 2

y^'=(x+1)/(e^{2y)}

y^{^{'}} = \frac{x + 1}{e ^{2 y}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=14y+1 ?
The solution for y^'=14y+1 is y=(e^{14t+c_{1}})/(14)-1/14