What is the solution for (dy)/(dx)+(e^{y^2})/(x^2y)=0,y(1)=0 ?

The solution for (dy)/(dx)+(e^{y^2})/(x^2y)=0,y(1)=0 is y=sqrt(-ln(-2/x+3)),y=-sqrt(-ln(-2/x+3))

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(dy)/(dx)+(e^{y^2})/(x^2y)=0,y(1)=0

\frac{d y}{d x} + \frac{e ^{y^{2}}}{x ^{2} y} = 0, y (1) = 0

y = - ln (- \frac{2}{x} + 3), y = - - ln (- \frac{2}{x} + 3)

Solution steps

\frac{d y}{d x} + \frac{e ^{y^{2}}}{x ^{2} y} = 0

Solve separable ODE:

y = - ln (- \frac{2}{x} + 3), y = - - ln (- \frac{2}{x} + 3)

y = - ln (- \frac{2}{x} + 3), y = - - ln (- \frac{2}{x} + 3)

x \frac{d y}{d x} = y x - x y cos (x)

\frac{d x}{d t} - x^{3} = x

y^{^{'}} + 20 x y = 0

(2 y + y x^{2}) d y = (x + x y^{2}) d x

y^{^{'}} = 4 e^{3 x} e^{- 2 y}

What is the solution for (dy)/(dx)+(e^{y^2})/(x^2y)=0,y(1)=0 ?
The solution for (dy)/(dx)+(e^{y^2})/(x^2y)=0,y(1)=0 is y=sqrt(-ln(-2/x+3)),y=-sqrt(-ln(-2/x+3))