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Popular >

y^'=2y,y(0)=3

Solution

y^{^{'}} = 2 y, y (0) = 3

Solution

y = 3 e^{2 t}

Solution steps

y^{'} (t) = 2 y

Solve separable ODE:

y = 3 e^{2 t}

y = 3 e^{2 t}

Popular Examples

xdy=(y^2-3y+2)dx

x d y = (y^{2} - 3 y + 2) d x

(dy)/(dx)=2e^{x-y},y(0)=ln(7)

\frac{d y}{d x} = 2 e^{x - y}, y (0) = ln (7)

y^'=(sqrt(x))/(e^y)

y^{^{'}} = \frac{x}{e ^{y}}

(dy)/(dx)=e^{x-2y}+1/(e^{2y)}

\frac{d y}{d x} = e^{x - 2 y} + \frac{1}{e ^{2 y}}

(dy)/y+(1/x+1)dx=0

\frac{d y}{y} + (\frac{1}{x} + 1) d x = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=2y,y(0)=3 ?
The solution for y^'=2y,y(0)=3 is y=3e^{2t}