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Popular >

y^'+x^3y=3x^3,y(0)=8

Solution

y^{^{'}} + x^{3} y = 3 x^{3}, y (0) = 8

Solution

y = 5 e^{- \frac{x ^{4}}{4}} + 3

Solution steps

y^{'} (x) + x^{3} y = 3 x^{3}

Solve separable ODE:

y = 5 e^{- \frac{x ^{4}}{4}} + 3

y = 5 e^{- \frac{x ^{4}}{4}} + 3

Graph

Popular Examples

(dP)/(dt)=0.062P

\frac{d P}{d t} = 0.062 P

y^'=(4cos(4x))/(3+2y),y(0)=-1

y^{^{'}} = \frac{4 cos ( 4 x )}{3 + 2 y}, y (0) = - 1

(dy)/(dx)=7-y^2

\frac{d y}{d x} = 7 - y^{2}

y*y^'-2x=sin(x),y(0)=6

y \cdot y^{^{'}} - 2 x = sin (x), y (0) = 6

(dy)/(dx)=(3y)/(2y^2+1),y=1,x=3

\frac{d y}{d x} = \frac{3 y}{2 y ^{2} + 1}, y = 1, x = 3

Frequently Asked Questions (FAQ)

What is the solution for y^'+x^3y=3x^3,y(0)=8 ?
The solution for y^'+x^3y=3x^3,y(0)=8 is y=5e^{-(x^4)/4}+3