What is the solution for (dy}{dx}=\frac{e^x-cos(2x))/y ,y(0)=2 ?

The solution for (dy}{dx}=\frac{e^x-cos(2x))/y ,y(0)=2 is y=sqrt(2e^x-sin(2x)+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=\frac{e^x-cos(2x))/y ,y(0)=2

\frac{d y}{d x} = \frac{e ^{x} - cos ( 2 x )}{y}, y (0) = 2

y = 2 e^{x} - sin (2 x) + 2

Solution steps

\frac{d y}{d x} = \frac{e ^{x} - cos ( 2 x )}{y}

Solve separable ODE:

y = 2 e^{x} - sin (2 x) + 2

y = 2 e^{x} - sin (2 x) + 2

(1 + 4 x) y ln (y) d x + (x + 2 x^{2}) d y = 0

y^{^{'}} = x e^{y - x^{2}}, y (0) = 0

t \frac{d y}{d t} = 15 y

y^{^{'}} + 2 x y = x, y (0) = 2

\frac{d y}{d x} = \frac{3 e ^{x}}{3 y + 1}

What is the solution for (dy}{dx}=\frac{e^x-cos(2x))/y ,y(0)=2 ?
The solution for (dy}{dx}=\frac{e^x-cos(2x))/y ,y(0)=2 is y=sqrt(2e^x-sin(2x)+2)