What is the solution for (dx)/(dt)+cos(t)x=cos(t) ?

The solution for (dx)/(dt)+cos(t)x=cos(t) is x=e^{-sin(t)+c_{1}}+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dx)/(dt)+cos(t)x=cos(t)

\frac{d x}{d t} + cos (t) x = cos (t)

x = e^{- s i n (t) + c_{1}} + 1

Solution steps

\frac{d x}{d t} + cos (t) x = cos (t)

Solve separable ODE:

x = e^{- s i n (t) + c_{1}} + 1

x = e^{- s i n (t) + c_{1}} + 1

5 x y \frac{d y}{d x} = 4, y > 0

\frac{d v}{d t} = \frac{2}{9} v

\frac{d y}{d x} = 4 cos (x) sec (y)

y^{^{'}} = \frac{x}{y + 1}

\frac{d y}{d x} = 5 x^{2} y, y > 0

What is the solution for (dx)/(dt)+cos(t)x=cos(t) ?
The solution for (dx)/(dt)+cos(t)x=cos(t) is x=e^{-sin(t)+c_{1}}+1