en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'-a^2y=0

Solution

y^{^{'}} - a^{2} y = 0

Solution

y = e^{a^{2} t + c_{1}}

Solution steps

y^{'} (t) - a^{2} y = 0

Solve separable ODE:

y = e^{a^{2} t + c_{1}}

y = e^{a^{2} t + c_{1}}

Popular Examples

(dy)/(dx)= x/(y+x^2y)

\frac{d y}{d x} = \frac{x}{y + x ^{2} y}

(dy)/(dx)=x(1+y)^2

\frac{d y}{d x} = x (1 + y)^{2}

(dy)/(dx)=(xln(x))/(y^2)

\frac{d y}{d x} = \frac{x ln ( x )}{y ^{2}}

(dy)/(dx)=(sin(x))/(sin(y))

\frac{d y}{d x} = \frac{sin ( x )}{sin ( y )}

\H(x)(x)^2x^2dx-2x^3d\H(x)=0

H (x) (x)^{2} x^{2} d x - 2 x^{3} d H (x) = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'-a^2y=0 ?
The solution for y^'-a^2y=0 is y=e^{a^2t+c_{1}}