What is the solution for (dy)/(dx)=-5/7 x^3y^2 ?

The solution for (dy)/(dx)=-5/7 x^3y^2 is y=-(28)/(-5x^4+c_{1)}

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(dy)/(dx)=-5/7 x^3y^2

\frac{d y}{d x} = - \frac{5}{7} x^{3} y^{2}

y = - \frac{28}{- 5 x ^{4} + c _{1}}

Solution steps

\frac{d y}{d x} = - \frac{5}{7} x^{3} y^{2}

Solve separable ODE:

y = - \frac{28}{- 5 x ^{4} + c _{1}}

y = - \frac{28}{- 5 x ^{4} + c _{1}}

y \frac{d y}{d x} + y^{3} = 1, y (4) = 0

(x^{2} + 25) y^{^{'}} = x y

x^{2} \frac{d y}{d x} + \frac{1}{x} y = \frac{2}{x} y^{- 3}

\frac{d x}{d y} = 1 - 0.4 x

y^{^{'}} - x^{2} cos (y) = x^{2}

What is the solution for (dy)/(dx)=-5/7 x^3y^2 ?
The solution for (dy)/(dx)=-5/7 x^3y^2 is y=-(28)/(-5x^4+c_{1)}