What is the integral of (sin(x)+sinh(x)) ?

The integral of (sin(x)+sinh(x)) is -cos(x)+cosh(x)+C

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integral of (sin(x)+sinh(x))

\int (sin (x) + sinh (x)) d x

- cos (x) + cosh (x) + C

Solution steps

\int sin (x) + sinh (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sin (x) d x + \int sinh (x) d x

\int sin (x) d x = - cos (x)

\int sinh (x) d x = cosh (x)

= - cos (x) + cosh (x)

Add a constant to the solution

= - cos (x) + cosh (x) + C

\frac{3 s + 12}{s ( s ^{2} + 4 )}

\int \frac{1}{( x ^{2} - 9 ) ^{\frac{3}{2}}} d x

\frac{\partial}{\partial x} (\frac{1}{e ^{x} - 1})

f (x) = e^{x} \cdot x

\frac{d}{d x} (x^{y^{x}})

What is the integral of (sin(x)+sinh(x)) ?
The integral of (sin(x)+sinh(x)) is -cos(x)+cosh(x)+C