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Popular >

y^'+x/2 y=x

Solution

y^{^{'}} + \frac{x}{2} y = x

Solution

y = e^{- \frac{x ^{2}}{4} + c_{1}} + 2

Solution steps

y^{'} (x) + \frac{x}{2} y = x

Solve separable ODE:

y = e^{- \frac{x ^{2}}{4} + c_{1}} + 2

y = e^{- \frac{x ^{2}}{4} + c_{1}} + 2

Popular Examples

y(dy)/(dx)=((x-e^x))/(e^{y^2)}

y \frac{d y}{d x} = \frac{( x - e ^{x} )}{e ^{y^{2}}}

(2x+1)y^'+y^2=0

(2 x + 1) y^{^{'}} + y^{2} = 0

(2x-1)dx+(3y+a)dy=0

(2 x - 1) d x + (3 y + a) d y = 0

y^'=(7x^2-1)/(7+9y)

y^{^{'}} = \frac{7 x ^{2} - 1}{7 + 9 y}

(dy)/(dt)=e^{t+y}

\frac{d y}{d t} = e^{t + y}

Frequently Asked Questions (FAQ)

What is the solution for y^'+x/2 y=x ?
The solution for y^'+x/2 y=x is y=e^{-(x^2)/4+c_{1}}+2