What is the solution for (dy)/(dx)=(yx+3x-y-3)/(xy-2x+4y-8) ?

The solution for (dy)/(dx)=(yx+3x-y-3)/(xy-2x+4y-8) is y=-5\W(-(x+4}{5e^{\frac{x+c_{1}+3)/5}})-3

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(dy)/(dx)=(yx+3x-y-3)/(xy-2x+4y-8)

\frac{d y}{d x} = \frac{y x + 3 x - y - 3}{x y - 2 x + 4 y - 8}

y = - 5 W (- \frac{x + 4}{5 e ^{\frac{x + c _{1} + 3}{5}}}) - 3

Solution steps

\frac{d y}{d x} = \frac{y x + 3 x - y - 3}{x y - 2 x + 4 y - 8}

Solve separable ODE:

y = - 5 W (- \frac{x + 4}{5 e ^{\frac{x + c _{1} + 3}{5}}}) - 3

y = - 5 W (- \frac{x + 4}{5 e ^{\frac{x + c _{1} + 3}{5}}}) - 3

\frac{d y}{d x} = \frac{9 ( 1 + x )}{x y}

x^{^{'}} = \frac{2 x}{t + 1}

y^{^{'}} + (x + 9) y = 0

\frac{d y}{d t} = - a y

\frac{d P}{d t} = 4 Pt, P (1) = 2

What is the solution for (dy)/(dx)=(yx+3x-y-3)/(xy-2x+4y-8) ?
The solution for (dy)/(dx)=(yx+3x-y-3)/(xy-2x+4y-8) is y=-5\W(-(x+4}{5e^{\frac{x+c_{1}+3)/5}})-3