What is the solution for y^'=ytan(x)-x^2y ?

The solution for y^'=ytan(x)-x^2y is y=(e^{(-x^3+c_{1})/3})/(cos(x))

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y^'=ytan(x)-x^2y

y^{^{'}} = y tan (x) - x^{2} y

y = \frac{e ^{\frac{- x ^{3} + c _{1}}{3}}}{cos ( x )}

Solution steps

y^{'} (x) = y tan (x) - x^{2} y

Solve separable ODE:

y = \frac{e ^{\frac{- x ^{3} + c _{1}}{3}}}{cos ( x )}

y = \frac{e ^{\frac{- x ^{3} + c _{1}}{3}}}{cos ( x )}

\frac{d v}{d t} = t^{2} v - 2 - 2 v + t^{2}

\frac{d y}{d x} + 100 y = 0

\frac{d y}{d x} = e^{x - y}, y (0) = ln (7)

x^{2} + 4 y \frac{d y}{d x} = 0

(\frac{y}{2 + 6 x}) d x + (ln (x) - 2) d y = 0

What is the solution for y^'=ytan(x)-x^2y ?
The solution for y^'=ytan(x)-x^2y is y=(e^{(-x^3+c_{1})/3})/(cos(x))