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Popular >

x^'=1+x^2

Solution

x^{^{'}} = 1 + x^{2}

Solution

x = tan (t + c_{1})

Solution steps

x^{'} (t) = 1 + x^{2}

Solve separable ODE:

x = tan (t + c_{1})

x = tan (t + c_{1})

Popular Examples

y^'+(cos(x))y=cos(x)

y^{^{'}} + (cos (x)) y = cos (x)

(x^2+1)(tan(y))(dy)/(dx)=x

(x^{2} + 1) (tan (y)) \frac{d y}{d x} = x

x(2y+1)dx-(x^2+1)dy=0

x (2 y + 1) d x - (x^{2} + 1) d y = 0

(8 x - 1) y^{^{'}} + 8 y = 0

cos(y)dx+e^{-x}sin(y)dy=0

cos (y) d x + e^{- x} sin (y) d y = 0

Frequently Asked Questions (FAQ)

What is the solution for x^'=1+x^2 ?
The solution for x^'=1+x^2 is x=tan(t+c_{1})