What is the solution for 3+2q(p)+(4+2p)q^'(p)=0 ?

The solution for 3+2q(p)+(4+2p)q^'(p)=0 is q(p)=(c_{1})/(2(4+2p))-3/2

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3+2q(p)+(4+2p)q^'(p)=0

3 + 2 q (p) + (4 + 2 p) q^{^{'}} (p) = 0

q (p) = \frac{c _{1}}{2 ( 4 + 2 p )} - \frac{3}{2}

Solution steps

3 + 2 q (p) + (4 + 2 p) q^{'} (p) = 0

Solve separable ODE:

q (p) = \frac{c _{1}}{2 ( 4 + 2 p )} - \frac{3}{2}

q (p) = \frac{c _{1}}{2 ( 4 + 2 p )} - \frac{3}{2}

\frac{d y}{d x} = sin (y)

\frac{d y}{d x} = (3 + y) (e^{x + 3} + x^{2})

x^{2} \frac{d y}{d x} + x y - x = 0

\frac{d y}{d x} = - (3 + y)

y^{5} \frac{d y}{d x} = 4 x^{2} y^{6} - 12 x^{2}

What is the solution for 3+2q(p)+(4+2p)q^'(p)=0 ?
The solution for 3+2q(p)+(4+2p)q^'(p)=0 is q(p)=(c_{1})/(2(4+2p))-3/2