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Popular >

5x+yy^'=0,y(2)=5

Solution

5 x + y y^{^{'}} = 0, y (2) = 5

Solution

y = - 5 x^{2} + 45

Solution steps

5 x + y y^{'} (x) = 0

Solve separable ODE:

y = - 5 x^{2} + 45

y = - 5 x^{2} + 45

Popular Examples

(dy)/(dx)=x^2(-6y+9)

\frac{d y}{d x} = x^{2} (- 6 y + 9)

x^3(dy)/(dx)=sec(y)

x^{3} \frac{d y}{d x} = sec (y)

(dy)/(dx)+(e^{x/2})/(25e^{5y)}=0

\frac{d y}{d x} + \frac{e ^{\frac{x}{2}}}{25 e ^{5 y}} = 0

(t^2-4)y^'+ty=0

(t^{2} - 4) y^{^{'}} + t y = 0

y^'=ysin(x),y(1)=2

y^{^{'}} = y sin (x), y (1) = 2

Frequently Asked Questions (FAQ)

What is the solution for 5x+yy^'=0,y(2)=5 ?
The solution for 5x+yy^'=0,y(2)=5 is y=sqrt(-5x^2+45)