What is the solution for (dy)/(dx)=-3/8 x^4y^4 ?

The solution for (dy)/(dx)=-3/8 x^4y^4 is y=-(2\sqrt[3]{5})/(\sqrt[3]{3(-3x^5+c_{1))}}

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(dy)/(dx)=-3/8 x^4y^4

\frac{d y}{d x} = - \frac{3}{8} x^{4} y^{4}

Solution steps

\frac{d y}{d x} = - \frac{3}{8} x^{4} y^{4}

Solve separable ODE:

y y^{^{'}} + x e^{x^{2}} = 0

(1 - x^{2}) \frac{d y}{d x} + x y = x, y (0) = 2

x y \frac{d y}{d x} = x^{2} + 1

(y - 1) sin (x) d x - d y = 0

\frac{d y}{d x} = 1 + y^{2}, y (0) = 0

What is the solution for (dy)/(dx)=-3/8 x^4y^4 ?
The solution for (dy)/(dx)=-3/8 x^4y^4 is y=-(2\sqrt[3]{5})/(\sqrt[3]{3(-3x^5+c_{1))}}