en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

e^yy^'-x^2=0

Solution

e^{y} y^{^{'}} - x^{2} = 0

Solution

y = ln (\frac{x ^{3}}{3} + c_{1})

Solution steps

e^{y} y^{'} (x) - x^{2} = 0

Solve separable ODE:

y = ln (\frac{x ^{3}}{3} + c_{1})

y = ln (\frac{x ^{3}}{3} + c_{1})

Popular Examples

y(169-x^2)^{1/2}dy=(169+y^2)^{1/2}dx

y (169 - x^{2})^{\frac{1}{2}} d y = (169 + y^{2})^{\frac{1}{2}} d x

(dx)/(dt)=-2x+1

\frac{d x}{d t} = - 2 x + 1

2y^'+y=0,y(0)=e-x/2

2 y^{^{'}} + y = 0, y (0) = e - \frac{x}{2}

(dy)/(dx)=(x^2-xy-x+y)/(xy-y^2)

\frac{d y}{d x} = \frac{x ^{2} - x y - x + y}{x y - y ^{2}}

(dy}{dx}=\frac{1+y^2)/x

\frac{d y}{d x} = \frac{1 + y ^{2}}{x}

Frequently Asked Questions (FAQ)

What is the solution for e^yy^'-x^2=0 ?
The solution for e^yy^'-x^2=0 is y=ln((x^3)/3+c_{1})