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Popular >

y^'=5e^{x-y}

Solution

y^{^{'}} = 5 e^{x - y}

Solution

y = ln (5 e^{x} + c_{1})

Solution steps

y^{'} (x) = 5 e^{x - y}

Solve separable ODE:

y = ln (5 e^{x} + c_{1})

y = ln (5 e^{x} + c_{1})

Popular Examples

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xy^'=ytan(ln(y))

x y^{^{'}} = y tan (ln (y))

(dy)/(dt)=-t/(2y)

\frac{d y}{d t} = - \frac{t}{2 y}

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(3 x y^{2} - x^{3}) \frac{d y}{d x} = 3 y^{3} - x^{2} y

(dy)/(dx)=(sin(3x))/(cos(4y))

\frac{d y}{d x} = \frac{sin ( 3 x )}{cos ( 4 y )}

Frequently Asked Questions (FAQ)

What is the solution for y^'=5e^{x-y} ?
The solution for y^'=5e^{x-y} is y=ln(5e^x+c_{1})