What is the solution for 2y^2y^'=3e^{2x} ?

The solution for 2y^2y^'=3e^{2x} is y=\sqrt[3]{(9e^{2x}+c_{1})/4}

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2y^2y^'=3e^{2x}

2 y^{2} y^{^{'}} = 3 e^{2 x}

Solution steps

2 y^{2} y^{'} (x) = 3 e^{2 x}

Solve separable ODE:

\frac{d y}{d x} = 0.02 y + 40000, y (0) = 2000000

y (25 - x^{2})^{\frac{1}{2}} d y = (25 + y^{2})^{\frac{1}{2}} d x

d y = 2 x y e^{x^{2}} d x

\frac{d y}{d x} = y (x^{2} + 6)

(1 - y^{2}) d x + x d y = 0

What is the solution for 2y^2y^'=3e^{2x} ?
The solution for 2y^2y^'=3e^{2x} is y=\sqrt[3]{(9e^{2x}+c_{1})/4}