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Popular >

y^'=(2/x-x)y

Solution

y^{^{'}} = (\frac{2}{x} - x) y

Solution

y = e^{- \frac{x ^{2}}{2} + c_{1}} x^{2}

Solution steps

y^{'} (x) = (\frac{2}{x} - x) y

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} + c_{1}} x^{2}

y = e^{- \frac{x ^{2}}{2} + c_{1}} x^{2}

Popular Examples

x^5(dy)/(dx)=3x^2sqrt(1-y^2)

x^{5} \frac{d y}{d x} = 3 x^{2} 1 - y^{2}

x^3+8y(dy)/(dx)=0

x^{3} + 8 y \frac{d y}{d x} = 0

(dy)/(dx)=y(8x^2+1)

\frac{d y}{d x} = y (8 x^{2} + 1)

1/(y^2)-(3x)/(y^3)(dy)/(dx)=0

\frac{1}{y ^{2}} - \frac{3 x}{y ^{3}} \frac{d y}{d x} = 0

y^{^{'}} = 2^{x - y}

Frequently Asked Questions (FAQ)

What is the solution for y^'=(2/x-x)y ?
The solution for y^'=(2/x-x)y is y=e^{-(x^2)/2+c_{1}}x^2