What is the solution for (dr)/(dt)= 4/3 pir^3 ?

The solution for (dr)/(dt)= 4/3 pir^3 is r=sqrt(-3/(8pi(t+c_{1)))},r=-sqrt(-3/(8pi(t+c_{1)))}

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(dr)/(dt)= 4/3 pir^3

\frac{d r}{d t} = \frac{4}{3} π r^{3}

r = - \frac{3}{8 π ( t + c _{1} )}, r = - - \frac{3}{8 π ( t + c _{1} )}

Solution steps

\frac{d r}{d t} = \frac{4}{3} π r^{3}

Solve separable ODE:

r = - \frac{3}{8 π ( t + c _{1} )}, r = - - \frac{3}{8 π ( t + c _{1} )}

r = - \frac{3}{8 π ( t + c _{1} )}, r = - - \frac{3}{8 π ( t + c _{1} )}

y^{^{'}} + r x y = 0

(\frac{( x + 1 ) ^{2} + 6}{4 ( x + 1 )}) (\frac{d y}{d x}) = tan (y)

\frac{d y}{d x} = - \frac{a y ( x )}{x}

y \cdot y^{^{'}} - 2 x = sin (x)

\frac{d y}{d x} = 0.125 (y - 3), y (0) = 5

What is the solution for (dr)/(dt)= 4/3 pir^3 ?
The solution for (dr)/(dt)= 4/3 pir^3 is r=sqrt(-3/(8pi(t+c_{1)))},r=-sqrt(-3/(8pi(t+c_{1)))}