What is the solution for (dy)/(dx)=(3x^2)/(e^y+1) ?

The solution for (dy)/(dx)=(3x^2)/(e^y+1) is y=-\W(1/(e^{-c_{1)-x^3}})+x^3+c_{1}

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(dy)/(dx)=(3x^2)/(e^y+1)

\frac{d y}{d x} = \frac{3 x ^{2}}{e ^{y} + 1}

y = - W (\frac{1}{e ^{- c_{1} - x^{3}}}) + x^{3} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{3 x ^{2}}{e ^{y} + 1}

Solve separable ODE:

y = - W (\frac{1}{e ^{- c_{1} - x^{3}}}) + x^{3} + c_{1}

y = - W (\frac{1}{e ^{- c_{1} - x^{3}}}) + x^{3} + c_{1}

y^{^{'}} = y^{2} t^{3}

\frac{d V}{d t} = 0.4 V

(3 x y^{2} + x^{3}) y^{^{'}} = 3 y^{3} + x^{2} y

(3 y^{2} x^{2} - 3 x^{2}) d x + (5 x^{3} y) d y = 0

\frac{d y}{d x} = ln (x^{y}), y (1) = 1

What is the solution for (dy)/(dx)=(3x^2)/(e^y+1) ?
The solution for (dy)/(dx)=(3x^2)/(e^y+1) is y=-\W(1/(e^{-c_{1)-x^3}})+x^3+c_{1}