What is the derivative of f(x)=2x^4-16x^2+6 ?

The derivative of f(x)=2x^4-16x^2+6 is 8x^3-32x

What is the first derivative of f(x)=2x^4-16x^2+6 ?

The first derivative of f(x)=2x^4-16x^2+6 is 8x^3-32x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = 2 x^{4} - 16 x^{2} + 6

8 x^{3} - 32 x

Solution steps

\frac{d}{d x} (2 x^{4} - 16 x^{2} + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) - \frac{d}{d x} (16 x^{2}) + \frac{d}{d x} (6)

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (16 x^{2}) = 32 x

\frac{d}{d x} (6) = 0

= 8 x^{3} - 32 x + 0

Simplify

= 8 x^{3} - 32 x

\int (3 cos (x) - e^{x} + \frac{5}{x}) d x

\frac{d y}{d x} = 0. 4^{\frac{x}{3}}

3 y^{^{''}} + 5 y^{^{'}} = 0

\frac{\partial}{\partial y} (x y^{8} + x^{2} + y^{4})

\int \frac{sin ( 9 ln ( t ) )}{t} d t

What is the derivative of f(x)=2x^4-16x^2+6 ?
The derivative of f(x)=2x^4-16x^2+6 is 8x^3-32x
What is the first derivative of f(x)=2x^4-16x^2+6 ?
The first derivative of f(x)=2x^4-16x^2+6 is 8x^3-32x