What is the solution for (dy}{dx}=-\frac{3cos(x))/y ?

The solution for (dy}{dx}=-\frac{3cos(x))/y is y=sqrt(-6sin(x)+c_{1)},y=-sqrt(-6sin(x)+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=-\frac{3cos(x))/y

\frac{d y}{d x} = - \frac{3 cos ( x )}{y}

y = - 6 sin (x) + c_{1}, y = - - 6 sin (x) + c_{1}

Solution steps

\frac{d y}{d x} = - \frac{3 cos ( x )}{y}

Solve separable ODE:

y = - 6 sin (x) + c_{1}, y = - - 6 sin (x) + c_{1}

y = - 6 sin (x) + c_{1}, y = - - 6 sin (x) + c_{1}

(x + 2)^{2} \cdot \frac{d y}{d x} = 4 x y

x y^{^{'}} = 5 y

7 x y \frac{d y}{d x} = 1, y > 0

\frac{d y}{d x} = \frac{ln ( x ) ( y ^{2} + 1 )}{x y}

y^{^{'}} = y \cdot x

What is the solution for (dy}{dx}=-\frac{3cos(x))/y ?
The solution for (dy}{dx}=-\frac{3cos(x))/y is y=sqrt(-6sin(x)+c_{1)},y=-sqrt(-6sin(x)+c_{1)}