What is the solution for (dy)/(dx)=(-1)/(x^2y^2) ?

The solution for (dy)/(dx)=(-1)/(x^2y^2) is y=\sqrt[3]{3/x+c_{1}}

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(dy)/(dx)=(-1)/(x^2y^2)

\frac{d y}{d x} = \frac{- 1}{x ^{2} y ^{2}}

Solution steps

\frac{d y}{d x} = \frac{- 1}{x ^{2} y ^{2}}

Solve separable ODE:

y^{^{'}} = \frac{8}{x} - \frac{6}{x} y

\frac{d y}{d x} = (\frac{x ^{2}}{y})

- y^{3} + y^{^{'}} + 0.5 y = 0

y^{^{'}} = (x + 2) (y - 1), y (0) = 2

\frac{d y}{y} + y e^{c o s (x)} sin (x) d x = 0

What is the solution for (dy)/(dx)=(-1)/(x^2y^2) ?
The solution for (dy)/(dx)=(-1)/(x^2y^2) is y=\sqrt[3]{3/x+c_{1}}