What is the solution for (x^2-9)(dy)/(dx)+xy=0,x^2-9>0 ?

The solution for (x^2-9)(dy)/(dx)+xy=0,x^2-9>0 is y=(c_{1})/(sqrt(x^2-9))

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(x^2-9)(dy)/(dx)+xy=0,x^2-9>0

(x^{2} - 9) \frac{d y}{d x} + x y = 0, x^{2} - 9 > 0

y = \frac{c _{1}}{x ^{2} - 9}

Solution steps

(x^{2} - 9) \frac{d y}{d x} + x y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - 9}

y = \frac{c _{1}}{x ^{2} - 9}

y^{^{'}} = 9 x^{2} y

\frac{d P}{d t} = 0.02 P

3 (x + 1) y^{2} y^{^{'}} = ln (x + 1), y (0) = 2

\frac{d y}{d x} = \frac{( 2 x ) y}{1 + x ^{2}}

\frac{d y}{d x} = \frac{5 x ^{4}}{3 y ^{2} e ^{y^{3}}}

What is the solution for (x^2-9)(dy)/(dx)+xy=0,x^2-9>0 ?
The solution for (x^2-9)(dy)/(dx)+xy=0,x^2-9>0 is y=(c_{1})/(sqrt(x^2-9))