What is the solution for y^'=(x+2)/(y^2) ?

The solution for y^'=(x+2)/(y^2) is y=\sqrt[3]{(3x^2)/2+6x+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(x+2)/(y^2)

y^{^{'}} = \frac{x + 2}{y ^{2}}

Solution steps

y^{'} (x) = \frac{x + 2}{y ^{2}}

Solve separable ODE:

y^{^{'}} = (y + 2)^{2}

\frac{d y}{d x} = 12 x y - 2 x

y^{^{'}} = (\frac{x}{y}) (\frac{y ^{2} + 1}{x ^{2} - 1})

\frac{d y}{d x} + 9 x e^{y} = 0

\frac{d x}{d t} + \frac{x}{100} = 75, x (0) = 5000

What is the solution for y^'=(x+2)/(y^2) ?
The solution for y^'=(x+2)/(y^2) is y=\sqrt[3]{(3x^2)/2+6x+c_{1}}