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Popular >

y^'=-4x^5e^y

Solution

y^{^{'}} = - 4 x^{5} e^{y}

Solution

y = - ln (\frac{2 x ^{6}}{3} - c_{1})

Solution steps

y^{'} (x) = - 4 x^{5} e^{y}

Solve separable ODE:

y = - ln (\frac{2 x ^{6}}{3} - c_{1})

y = - ln (\frac{2 x ^{6}}{3} - c_{1})

Popular Examples

(dy)/(dx)=-x/(5y)

\frac{d y}{d x} = - \frac{x}{5 y}

(1-x^2)(dy)/(dx)+xy=xy^2

(1 - x^{2}) \frac{d y}{d x} + x y = x y^{2}

\frac{d N}{d t} = 2 N

(1+5e^{2x})(y^2-4)y^'=e^{2x}(y+2)

(1 + 5 e^{2 x}) (y^{2} - 4) y^{^{'}} = e^{2 x} (y + 2)

(dy)/(dx)=(xy)/(1+x^2)

\frac{d y}{d x} = \frac{x y}{1 + x ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=-4x^5e^y ?
The solution for y^'=-4x^5e^y is y=-ln((2x^6)/3-c_{1})