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Popular >

y^'=2y-t

Solution

y^{^{'}} = 2 y - t

Solution

y = \frac{2 t + 1}{4} + c_{1} e^{2 t}

Solution steps

y^{'} (t) = 2 y - t

Solve linear ODE:

y = \frac{2 t + 1}{4} + c_{1} e^{2 t}

y = \frac{2 t + 1}{4} + c_{1} e^{2 t}

Popular Examples

f(x)=(ln(x))/(x^9)

f (x) = \frac{ln ( x )}{x ^{9}}

derivative of (6x^2+1/(x^2+8))

\frac{d}{d x} (\frac{6 x ^{2} + 1}{x ^{2} + 8})

derivative of y=cos((pix)^8)derivative of

y = cos ((π x)^{8})

integral from-1 to 2 of x^2(x^3+1)^2

\int_{- 1}^{2} x^{2} (x^{3} + 1)^{2} d x

(dy)/(dx)=100x(y+2)

\frac{d y}{d x} = 100 x (y + 2)

Frequently Asked Questions (FAQ)

What is the solution for y^'=2y-t ?
The solution for y^'=2y-t is y=(2t+1)/4+c_{1}e^{2t}