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Popular >

y^'=(x-1)/(y^2)

Solution

y^{^{'}} = \frac{x - 1}{y ^{2}}

Solution

Solution steps

y^{'} (x) = \frac{x - 1}{y ^{2}}

Solve separable ODE:

Popular Examples

(dy)/(dx)=((3e^x))/((3y+1))

\frac{d y}{d x} = \frac{( 3 e ^{x} )}{( 3 y + 1 )}

(dy)/(dx)= 1/(y+x^2y)

\frac{d y}{d x} = \frac{1}{y + x ^{2} y}

(dy)/(dx)=6-y/(20)

\frac{d y}{d x} = 6 - \frac{y}{20}

y^'+3y=1,3sin(2t)y(0)=6

y^{^{'}} + 3 y = 1, 3 sin (2 t) y (0) = 6

(dy)/(dx) 1/x+1/y =1

\frac{d y}{d x} \frac{1}{x} + \frac{1}{y} = 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=(x-1)/(y^2) ?
The solution for y^'=(x-1)/(y^2) is y=\sqrt[3]{(3x^2)/2-3x+c_{1}}