What is the solution for (dy)/(dt)+2y=5,y(0)=1 ?

The solution for (dy)/(dt)+2y=5,y(0)=1 is y=-(3e^{-2t})/2+5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)+2y=5,y(0)=1

\frac{d y}{d t} + 2 y = 5, y (0) = 1

y = - \frac{3 e ^{- 2 t}}{2} + \frac{5}{2}

Solution steps

\frac{d y}{d t} + 2 y = 5

Solve separable ODE:

y = - \frac{3 e ^{- 2 t}}{2} + \frac{5}{2}

y = - \frac{3 e ^{- 2 t}}{2} + \frac{5}{2}

\frac{d y}{d x} = \frac{3 x + x y ^{2}}{2 y + x ^{2} y}, y (2) = 1

\frac{d y}{d x} = 800 y

1 - x^{2} d y - x y d x = 0, y (1) = 2

\frac{d y}{d x} + y = 2, y (0) = 0

\frac{d y}{d x} = \frac{3 x ^{2}}{2 y}

What is the solution for (dy)/(dt)+2y=5,y(0)=1 ?
The solution for (dy)/(dt)+2y=5,y(0)=1 is y=-(3e^{-2t})/2+5/2