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Popular >

y^'=2-0.1y

Solution

y^{^{'}} = 2 - 0.1 y

Solution

y = - 10 e^{\frac{- t - c _{1}}{10}} + 20

Solution steps

y^{'} (t) = 2 - 0.1 y

Solve separable ODE:

y = - 10 e^{\frac{- t - c _{1}}{10}} + 20

y = - 10 e^{\frac{- t - c _{1}}{10}} + 20

Popular Examples

(dx)/(dt)=x^2+1/25 ,x(0)=-3

\frac{d x}{d t} = x^{2} + \frac{1}{25}, x (0) = - 3

y = (x + 1) y^{^{'}} - 1

e^yy^'=((ln(t))^2)/t ,y(1)=ln(4)

e^{y} y^{^{'}} = \frac{( ln ( t ) ) ^{2}}{t}, y (1) = ln (4)

(y^2-1)dx+xdy=0

(y^{2} - 1) d x + x d y = 0

y^3(dy)/(dx)=3x^4y^4-12x^4

y^{3} \frac{d y}{d x} = 3 x^{4} y^{4} - 12 x^{4}

Frequently Asked Questions (FAQ)

What is the solution for y^'=2-0.1y ?
The solution for y^'=2-0.1y is y=-10e^{(-t-c_{1})/(10)}+20